Description
The functx:last-node function returns the node in the sequence that appears last in document order (regardless of their order in the sequence). If nodes in the sequence are from multiple documents, the choice of which document is last is implementation-dependent.
Arguments and Return Type| Name | Type | Description |
|---|
$nodes |
node()* |
the sequence of nodes |
| return value |
node()? |
XQuery Function Declaration| See XSLT definition. | | XQuery Syntax for July 2004 - January 2007 (1.0): |
|---|
declare namespace functx = "http://www.functx.com";
declare function functx:last-node
( $nodes as node()* ) as node()? {
($nodes/.)[last()]
} ; | | XQuery Syntax for May 2003: |
|---|
declare namespace functx = "http://www.functx.com"
define function last-node
( $nodes as node()* ) as node()? {
($nodes/.)[fn:last()]
} |
Exampleslet $in-xml := | <authors>
<author>
<fName>Kate</fName>
<lName>Jones</lName>
</author>
<author>
<fName>John</fName>
<lName>Doe</lName>
</author>
</authors> | return |
| XQuery Example | Results |
|---|
functx:last-node($in-xml//fName)
|
<fName>John</fName>
|
functx:last-node(
($in-xml//lName,
$in-xml//fName) )
|
<lName>Doe</lName>
|
See AlsoHistory |
|
