Description
The functx:sequence-node-equal function returns a boolean value indicating whether the two arguments have the same nodes, in the same order. They are compared based on node identity, not their contents.
Arguments and Return Type| Name | Type | Description |
|---|
$seq1 |
node()* |
the first sequence of nodes |
$seq2 |
node()* |
the second sequence of nodes |
| return value |
xs:boolean |
XQuery Function Declaration| See XSLT definition. | | XQuery Syntax for July 2004 - January 2007 (1.0): |
|---|
declare namespace functx = "http://www.functx.com";
declare function functx:sequence-node-equal
( $seq1 as node()* ,
$seq2 as node()* ) as xs:boolean {
every $i in 1 to max((count($seq1),count($seq2)))
satisfies $seq1[$i] is $seq2[$i]
} ; | | XQuery Syntax for May 2003: |
|---|
declare namespace functx = "http://www.functx.com"
define function sequence-node-equal
( $seq1 as node()* ,
$seq2 as node()* ) as xs:boolean {
every $i in 1 to fn:max((fn:count($seq1),fn:count($seq2)))
satisfies $seq1[$i] is $seq2[$i]
} |
Exampleslet $in-xml := | <authors>
<author>
<fName>Kate</fName>
<lName>Jones</lName>
</author>
<author>
<fName>John</fName>
<lName>Doe</lName>
</author>
</authors> | let $anAuthor := | <author>
<fName>Kate</fName>
<lName>Jones</lName>
</author> | return |
| XQuery Example | Results | Explanation |
|---|
functx:sequence-node-equal(
$in-xml/author/*, $in-xml/*/*)
|
true
|
functx:sequence-node-equal(
$in-xml/author,
($in-xml/author[2],$in-xml/author[1]))
|
false
|
The order of the nodes is different. |
functx:sequence-node-equal(
$in-xml/author[1],$anAuthor)
|
false
|
Although the nodes have the same content, they are not the same node. |
See AlsoHistory |
|
